Graph between `log x//m` and `log p` is a straight line inclined at an angle of `45^@` . When pressure is `0.5 atm` and `1n k = 0.693`, the amount of solute adsorbed per gram of adsorbent will be:

Plot of "log" x/m against log p is a straight line inclined at an angle of 45^@ . When the pressure is 0.5atm and k value is 10, the amount of solute adsorbed per gram of adsorbent will be

Plot of log (x/m) against log P is a straight line inclined at an angle of 45^@ . When the pressure is 0.5 atm and Freundlich parameter, kis 10, the amount of solute adsorbed per gram of adsorbent will be: (log 5 = 0.6990)

Plot of log(x/m) against log P is a straight line inclined at an angle of 45^(@) . When the pressure is 0.5 atm and Freundlich parameter ,K is 10, the amount of solute adsorbed per gram of adsorbent will be : (log 5=0.6990 )

Plot of log against log P is a straight line inclined at an angle of 45^(@) . When the pressure is 0.5 atm and Freundlich parameter ,K is 10, the amount of solute adsorbed per gram of adsorbent will be : (log 5=0.6990 )