Three `alpha-`particle and one `beta-`particle decaying takes place in series from an isotope `._88 Ra^238`. Finally the isotope obtained will be.

Thorium isotope ._(90)Th^(232) emits some alpha -particle and some beta -particle and gets transformed into lead isotope ._(82)Pb^(200) . Find the number of alpha -and beta -particles emitted.

In the actinium, series, the first member ._(92)U^(235) emits in succession 7 alpha particles and 4 beta particles and gets converted into a stable lead isotope lead isotope. Find the atomic number and mass number of the lead isotope so formed.

Radioactive isotope Th^232 (Z = 90) emits six alpha -particles and four beta -particles successively. What will be the mass number and atomic number of the isotope thus produced? Identify the element.

In a nuclear decay, a nucleus emits one alpha -particle and then two beta -particles one after another. Show that the final nucleus is an isotope of former nucleus.

In a radioactive disintegration a nucleus emits an alpha -particle first and then two beta -particles. Show that the final nucleus thus formed is the isotope of the first.

A uranium nucleus ._(92)U^(238) emits and alpha -particle and a beta -particle in succession. The atomic number and mass number of the final nucleus will be

A uranium nucleus ._(92)U^(238) emits and alpha -particle and a beta -particle in succession. The atomic number and mass number of the final nucleus will be

A uranium nucleus ""_(92)U^(238) emits an alpha particle and a beta - particle in succession. The atomic number and mass number of the final nucleus will be