In an hydrogen atom, the electron revolves around the nucles in an orbit of radius `0.53 xx 10^(-10) m`. Then the electrical potential produced by the nucleus at the position of the electron is

In a hydrogen atom the electron revolves around the proton in an orbit of 0.53Å . The potential produced by the electron on the nuleus is

(a) Obtain an expression for the equivalent capacitance when three capacitors are connected in parallel (b) An electron revolves around the nucleus of hydrogen atom in a circular orbit of radius 5 xx 10^(-11)m. Calculate : (i) intensity of electric field of the nucleus at the position of the electron. (ii) electrostatic potential energy of the hydrogen nucleus and electron system.

In hydrogen atom, the electron makes 6.6 xx 10^(15) revolutions per second around the nucleus in an orbit of radius 0.5 xx 10^(-10)m . It is equivalent to a current nearly

In hydrogen atom, the electron makes 6.6 xx 10^(15) revolutions per second around the nucleus in an orbit of radius 0.5 xx 10^(-10)m . It is equivalent to a current nearly

In hydrogen atom, the electron makes 6.6 xx 10^(15) revolutions per second around the nucleus in an orbit of radius 0.5 xx 10^(-10)m . It is equivalent to a current nearly

The classical method of a hydrogen atom in its normal, unexcited configuration has an electron that revolves around a proton at a distance of 5.3 xx 10^(11)m . (a) What is the electric potential due to the proton at the position of electron ? (b) Determine the electrostatic potential energy between the two particles.

The classical method of a hydrogen atom in its normal, unexcited configuration has an electron that revolves around a proton at a distance of 5.3 xx 10^(11)m . (a) What is the electric potential due to the proton at the position of electron ? (b) Determine the electrostatic potential energy between the two particles.

An electron in an atom revolves around the nucleus in an orbit of radius 0*5 Å . Calculate the equivalent magnetic moment if the frequency of revolution of electron is 10^(10)MHz

The electon in the hydrogen atom revolves around the nucleus in an orbit of radius 0.5 A what is the equivalent magnetic moment if the frequency of revolution of the electron is 10^(10) MHz ?

An electron in an atom revolves around the nucleus in an orbit of radius 0*53Å . Calculate the equivalent magnetic moment, if the frequency of revolution of electron is 6*8xx10^9MHz .