the work function of metal is W and `lamda` is the wavelength of the incident radiation. There is no emission of photoelecrons when

The work function of a metal is 4 eV. What should be the wavelength of the incident radiation for the emission of photoelectrons of zero velocity ?

If the work function of a metal is 'phi' and the frequency of the incident light is 'v' , there is no emission of photoelectron if

If the work function of a metal is 'phi' and the frequency of the incident light is 'v' , there is no emission of photoelectron if

If the work function of a metal is 'phi' and the frequency of the incident light is 'v' , there is no emission of photoelectron if

Photoelectric threshold wavelength for a metal is 2100Å . If the wavelength of incident radiation be 1800 Å , will there be any emission of photoelectrons?

Work function of a photosensitive metal is 3eV. The wavelength of incident radiations which can just eject photoelectrons from the metal is

Is there a time lag between the incident radiation and the emission of electrons from a metal?

Work function of a photosensitive metal is 1.875 eV. Calculate the wavelength of incident light, which will just cause the emission of photoelectrons.

A radiation is incident on a metal surface of work function 2.3 eV. The wavelength of incident radiation is 60 nm, then the number of photoelectrons is