The wire of potentiometer has resistance `4 Omega` and length 1m. It is connected to a cell of e.m.f. 2V and internal resistance `1 Omega`. The current flowing through the potentiometer wire is

The wire of potentiometer has resistance 4Omega and length 1m . It is connected to a cell of emf 2 volt and internal resistance 1Omega . If a cell of emf 1.2 volt is balanced by it, the balancing length will be

The wire of potentiometer has resistance 4Omega and length 1m . It is connected to a cell of emf 2 volt and internal resistance 1Omega . If a cell of emf 1.2 volt is balanced by it, the balancing length will be

The wire of potentiometer has resistance 4Omega and length Im. It is connected to a cell of EMF 2V and internal resistance 1Omega . Ifa cell ofEMF 1.2V is balanced byit, the balancing length will be:

The potentiometer wire of resistance R is connected in series with a cell of e.m.f. E and of resistance R_(h) . The current flowing through the potentiometer wire is

A resistance of 4 Omega and a wire of length 5 meters and resistance 5 Omega are joined in series and connected to a cell of e.m.f. 10 V and internal resistance 1 Omega . A parallel combination of two identical cells is balanced across 300 cm of wire. The e.m.f. E of each cell is

A resistance of 4 Omega and a wire of length 5 meters and resistance 5 Omega are joined in series and connected to a cell of e.m.f. 10 V and internal resistance 1 Omega . A parallel combination of two identical cells is balanced across 300 cm of wire. The e.m.f. E of each cell is

A potentiometer wire has a length of 4 and a resistance of 8 ohm. It is connected in series with a cell of e.m.f. 2 V and internal resistance 2 ohm. The potential drop per unit length of the wire is

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.