A body cools from `50^(@)C` to `49.9^(@)C` in 5 s. the temperature of the surroundings is `30^(@)C`. How long will the body, take to cool from `40^(@)C` to `39.9^(@)C`?

A body takes 4 min. to cool from 61^(@)C to 59^(@)C . If the temperature of the surroundings is 30^(@)C , the time taken by the body to cool from 51^(@)C to 49^(@)C is :

A body takes 5 minutes to cool from 90^(@)C to 60^(@)C . If the temperature of the surroundings is 20^(@)C , the time taken by it to cool from 60^(@)C to 30^(@)C will be.

A pan filled with hot food cools from 50^(@)C to 48^(@)C in 5 s when the room temperature is at 30^(@)C . How long will it take to cool from 40^(@)C to 39^(@)C ?

A body cools from 80°C to 50°C in 5 minutes.If the temperature of the surrounding is 20°C ,Calculate the time it takes to cool from 60°C to 30°C .

A body cools according to Newton's law from 100^@ C to 60^@ C in 20 minutes.The temperature of the surrounding being 20^@ C ,how long will it take to cool down to 30^@ C ?

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body cools from 50^(@)C to 46^(@)C in 5 min and to 40^(@)C in the next 10 min. then the temperature of the surrounding is

A body cools from 70^(@)C to 50^(@)C in 6 minutes when the temperature of the surrounding is 30^(@)C . What will be the temperature of the body after further 12 minutes if coolilng proseeds ac cording to Newton's law of cooling ?