The entropy if vaporisation of benzene is `85JK^(-1) mol^(-1)`. When 117g benzene vaporizes at its's normal boiling point, the entropy change in surrounding is:

The entropy of vaporization of a liquid is 58 J K^(-1) mol^(-1) .If 100 g of its vapour condenses at its boiling point of 123^(@)C , the value of entropy change for the process is (molar mass of the liquid = 58 mol^(-1) ).

The enthalpy of vaporisation of water is 186.5 kJ mol^(-1) . The entropy of its vaporisation will be :

The enthalpy of vaporisation of benzene (C_(6)H_(6)) is 30.8 kJ mol^(-1) at its boiling point (80.1^(@)C) . Calculate the entropy change in going from: a. liquid to vapour and b. vapour to liquid at 80.1^(@)C .

The enthalpy of vaporisation of benzene (C_(6)H_(6)) is 30.8 kJ mol^(-1) at its boiling point (80.1^(@)C) . Calculate the entropy change in going from: a. liquid to vapour and b. vapour to liquid at 80.1^(@)C .

If the enthalpy of vaporisation of water is 186.5 kJ mol^(-1) , then entropy of its vaporisation will be

If the enthalpy of vaporisation of water is 186.5 J mol^(-1) , then entropy of its vaporisation will be

Enthalpy of vaporization of benzene is + 35.3 kJ mol^(-1) at its boiling point, 80^(@)C . The entropy change in the transition of the vapour to liquid at its boilling point [in JK^(-1) mol^(-1) ] is ……….