An aqueous solution of a protein has an osomatic pressure of 3.8 mm of Hg at temperature of `300K` . If concentration of protein is `(1)/(49.26) %` w/v , then calculate molecular mass of protein.

2000 cm^3 of an aqueous solution of a protein contains 1.26 g of the protein. The osmotic pressure of such a solution at 300K is found to be 2.57 … 10^(-3) bar. Calculate the molar mass of the protein.

200 cm^(3) of an aqueous solution of a protein contains 1.26 g of the protein. The osmotic pressure of such a solution at 300 K is found to be 2.57 xx10^(-3) bar. Calculate the molar mass of the protein.

200 cm^(3) of an aqueous solution of a protein contains 1.26 g of the protein. The osmotic pressure of such a solution at 300 K is found to be 2.57 xx10^(-3) bar. Calculate the molar mass of the protein.

200" cm"^(2) of an aqueous solution of a protein contains 1.26 g of the protein. The oxmotic pressure of such a solution at 300 K is found to be 2.57xx10^(-3) bar. Calculate the molar mass of the protein.

200 cm^3 of an aqueous solution of a protein contains 1.26g of the protein . The osmotic pressure of such a solution at 300K is found to be 2.7 xx 10^-3 bar. Calculate the molar mass of the protein (R=0.083 L bar mol^-1 K^-1 )

200 mL of a very dilute aqueous solution of a protein contains 1.9 gm of the protein . If osmotic rise of such a solution at 300K is found to be 38 mm of solution then calculate molar mass of the protein . (Take R = 0.008 L atm mol^(-1) K^(-1) )