-9-(-6) = ?

(-9) x 6 + (-9) x 4 = ?

Fill in the blanks (-9) xx {(-1)-(-6)} square (-9) xx (-1) - (-9) xx (-6)

A square is inscribed in the circle x^2+y^2-2x+4y-93=0 with its sides parallel to the coordinate axes. The coordinates of its vertices are (-6,-9),(-6,5),(8,-9),(8,5) (-6,-9),(-6,-5),(8,-9),(8,5) (-6,-9),(-6,5),(8,9),(8,5) (-6,-9),(-6,5),(8,-9),(8,-5)

A square is inscribed in the circle x^2+y^2-2x+4y-93=0 with its sides parallel to the coordinate axes. The coordinates of its vertices are (-6,-9),(-6,5),(8,-9),(8,5) (-6,-9),(-6,-5),(8,-9),(8,5) (-6,-9),(-6,5),(8,9),(8,5) (-6,-9),(-6,5),(8,-9),(8,-5)

A square is inscribed in the circle x^(2)+y^(2)-2x+4y-93=0 with its sides parallel to the coordinate axes.The coordinates of its vertices are (-6,-9),(-6,-5),(8,-9),(8,5)(-6,-9),(-6,-5),(8,-9),(8,5)(-6,-9),(-6,5),(8,-9),(8,-5)(-6,-9),(-6,5),(8,-9),(8,-5)

Let us simplify using formula:- (4a^2 -9) (4a^2 - 6a + 9) (4a^2 + 6a + 9)

Multiply : (-9) xx (6)

Solve the following simple Equations : (9x)/(6)=9

Let R={(3,3),(6,6),(9,9),(12,12),(6,12),(3,9(,(3,12),(3,6)} be relation on the set A={3,6,9,12} . The relation is-