A copper wire and an aluminium wire has lenghts in the ratio `3:2` diameter in the ratio `2:3` and froce applied in the ratio `4:5` find the ratio of the increase in length of the two wires
`TY_(AT) = 7xx10^(10) N//m^(2), Y_(Cu) = 11xx10^(10) N//m^(2)`

A copper wire and an aluminium wire have lengths in the ratio 3:2, diameters in the ratio 4:3, Forces in the ratio 4:5. Find the ratio of increase in length of the two wires. (Y_(cu)=1.1xx10^(11)N//m^(-2),Y_(AI)=0.7xx10^(11)Nm^(-2)

A copper wire and an aluminium wire have lengths in the ratio 5:2 diameters in the ratio 4:3 and forces applied in the ratio 4:5. Find the ratio of increase in length of the copper wire to that aluminium wier. (Let Y_(Cu)=1.1xx10^(11)Nm^(-2),Y_(Al)=0.7xx10^(11)Nm^(-2) )

Two copper wires have their masses in the ratio 2 : 3 and the lengths in the ratio 3 : 4. The ratio of the resistances is