period the function `f(x)=(sin{sin(n x)})/(tan (x/n))`, n`in` N, is `6pi` then `n=`--------

If the period of ( cos ( sin(nx)))/(tan""(x//n)), n in N is 6pi then n=

If the period of (sin(nx))/(tan((x)/(n))), where n in1, is 6 pi, then

The period of the function f(x)=cos(pi(x)/(n!))-sin(pi(x)/((n+1)!)) is

If the period of (cos(sin(nx)))/(tan((x)/(n))),n in N, is 6 pi then n=3( b) 2(c)6(d)1

" If the function "f(x)=(cos(sin(nx)))/(tan((x)/(n)))" has fundamental period "8 pi," then "n" equals "(n in N)

The function f(x)=sin""(pix)/(n!)-cos""(pix)/((n+1)!) is :

The value of n in N for which the function f(x) = (sin(nx))/(sin (x/n)) has a period of 4pi , is

If the function f(x ) = (sin n x)/( sin ((x )/(n ))) n EE Z has period pi then show that n is 2.

The value of integer n for which the function f(x)=(sin x)/(sin((x)/(n))) has 4 pi its period is

If the period of (cos(sin(n x)))/(tan(x/n)),n in N ,i s6pi , then n= (a)3 (b) 2 (c) 6 (d) 1