A nucleus X, initially at rest, undergoes alpha-decay according to the equation.
`_92^AXrarr_Z^228Y+alpha`
(a) Find the values of A and Z in the above process.
(b) The alpha particle produced in the above process is found in move in a circular track of during the process and the binding energy of the parent nucleus X.
Given that `m(Y)=228.03u`, `m(`_0^1n)=1.009u`
`m(`_2^4He)=4.003u`, `m(`_1^1H)=1.008u`

A nucleus X, initially at rest , undergoes alpha dacay according to the equation , _(92)^(A) X rarr _(2)^(228)Y + a (a) Find the value of A and Z in the above process. (b) The alpha particle producted in the above process is found to move in a circular track of radius 0.11 m in a uniform mmagnatic field of 3 Tesia find the energy (in MeV) released during the process and the binding energy of the patent nucleus X Given that : m (gamma) = 228.03 u, m(_(0)^(1)) = 1.0029 u. m (_(2)^(4) He) = 4.003 u , m (_(1)^(1) H) = 1.008 u

A nuclider X, initally at rest, undergoes alpha -decay according to the equation 92^(X^(Ato))z ^(Y^(238))+ sigma. The alpha -particle produced in the above process is found to move in a circular track of radiuc 0.11 m in a uniform magnetic field of 3T. Find the binding energy per nucleon (in Mev) of the daughter nuclide Y. Given that (m (y) =228.03u, m(_(2)He^(4)) =4.003u, m (_(0)n^(1)) =1.009 u , m (_(1)H^(1)) =1 amu = 931.5 MeV//c^(2) =1.66 xx10^(-27)kg

A nucleus X of mass M. intially at rest undergoes alpha decay according to the equation _(Z)^(A)Xrarr._(Z-2)^(A-4)Y+._(2)^(4)He The alpha particle emitted in the above proces is found to move in a circular track of radius r in a uniform magnetic field B. Then (mass and charge of alpha particle are m and q respectively)

A nucleus X^232 initially at rest undergoes alpha decay, the alpha -particle produced in above process is found to move in a circular track of radius 0.22 m in a uniform magnetic field of 1.5 T. Find Q value of reaction.

The binding energy of alpha -particle is ( if m_p=1.00785u , m_n=1.00866u and m_alpha=4.00274u )