`(7+i5)(7-i5)`

Perform the following by the indicated operations. Express the result in the form x + iy,where x, y are real numbers i = sqrt(-1) : (7+ 5i)(7- 5i) .

The from a+ib:(7-i2)-(4+i)+(-3+i5)

Show that ((19- 7i)/(9 + i))^(12) + ((20 - 5i)/(7 - 6i))^(12) is real.

If i=sqrt(-1) , then (7+5i)(-2-6i)=

The from a+ib is given : (7-i2)-(4+i)+(-3+i5) simplify it.

If x +iy =(3+5i)/(7-6i) then y is equal to

If x + iy = (3 + 5i)/(7-6i), they y =

In the following, perform the indicated operations and write the result in the form x+iy: (i) (7-2i)-(3+2i)+(7+8i) (ii) 3-4i+2i-(8+7i) (iii) (7-2i)-(4+i)+(-3+5i)

Write the conjugate of complex number (5i)/(7+i)

Write the conjugate of the following complex number (5i)/(7+i)