`0.25(4f-3)=0.05(10f-9)`

Simplify and solve the linear equations.025(4f-3)=005(10f-9)

Simplify and solve the following linear equations : 0.25 (4y-3)=0.5 y-9

((0.05)/(0.25)+(0.25)/(0.05))^(3)=?( a) 139.4(b)140(c)140.6(d)143.9

Calculate the order of the reaction in A and B :- {:(A,,,B,,,Rate),(("mol"//1),,,("mol"//1),,,),(0.05,,,0.05,,,1.2xx10^(-3)),(0.10,,,0.05,,,2.4xx10^(-3)),(0.05,,,0.10,,,1.2xx10^(-3)):}

Calculate the order of the reaction in A and B :- {:(A,,,B,,,Rate),(("mol"//1),,,("mol"//1),,,),(0.05,,,0.05,,,1.2xx10^(-3)),(0.10,,,0.05,,,2.4xx10^(-3)),(0.05,,,0.10,,,1.2xx10^(-3)):}

Let f(x)={{:(,3^x,at,-1lt x lt0),(,4,at,0 le x lt 1),(,3x-1, at,1 le x le 3):} Find f(2), f(0), f(0.5), f(-0.5), f(3).

Simplify: [(2 10/27))^(-2/3) ÷ (11 1/9))^(-0.5)] +[(6.25)^(0.5) ÷ (-4)^(-1)]