Home
Class 12
CHEMISTRY
The number of geometrical isomers of th...

The number of geometrical isomers of the compound,
`CH_(3)CH=CH-CH=CHCH_(3)` is-

Promotional Banner

Similar Questions

Explore conceptually related problems

The number of geometrical isomers of the molecule CH_(3)-CH=CH-CH=NH is

The number of geometrical isomers of the compound is C_(6)H_(5)-CH=CH-CH=CH-COOH

The number of geometrical isomers of the compound is C_(6)H_(5)-CH=CH-CH=CH-COOH

The number of geometrical isomers in the following compound CH_3 -CH=CH-CH=CH-C_2H_5 is

No.of geometrical isomers possible for the compound CH_(3)-CH=CH-CH=CH-C_(2)H_(4)

The number of optically active isomers of the compounds, CH_(3)CH(OH)CH(OH)CH_(3) is

No. of geometrical isomers possible for the compound CH_(3)-CH=CH-CH=CH-C_(2)H_(5)

Find the number of geometrical isomers of the given compound . C_(6)H_(5) - CH = CH - CH-CH = CH - CH = CH - COOH