In the given figure, ABCD is a parallelogram in which AN and CP are perpendiculars on diagonal BD. Prove that :
(i) `DeltaADN =DeltaCBP`
`(ii) AN=CP`

ABCD is a parallelogram and AP and CQ are perpendiculars from vertex A and C on diagonal BD. Show that (i) DeltaAPB~=DeltaCQD (ii) AP=CQ .

ABCD is a parallelogram and AP and CQ are perpendicular from vertices A and C on diagonal BD. Show that DeltaAPB approx DeltaCQD AP=CQ

ABCD is a parallelogram AP and CQ are perpendiculars drawn from vertices A and C on diagonal BD (see figure)..Show that : i) DeltaAPB = DeltaCQD .

ABCD is a parallelogram AP and CQ are perpendiculars drawn from vertices A and C on diagonal BD (see figure) show that (i) DeltaAPB ~= DeltaCQD (ii) AP = CQ

ABCD is a parallelogram AP and CQ are perpendiculars drawn from vertices A and C on diagonal BD (see figure) show that (i) DeltaAPB ~= DeltaCQD (ii) AP = CQ

ABCD is a parallelogram AP and CQ are perpendiculars drawn from vertices A and C on diagonal BD (see figure) show that (i) DeltaAPB ~= DeltaCQD (ii) AP = CQ

ABCD is a parallelogram AP and CQ are perpendiculars drawn from vertices A and C on diagonal BD (see figure) show that (i) DeltaAPB ~= DeltaCQD (ii) AP = CQ

The given figure shows parallelogram ABCD. Points M and N lie in diagonal BD such that DM=BN. Prove that:

In the given figure ABCD is a trapezium with AB || Dc and AD = BC prove that diagonal AC = diagonal BD