`f((2tanx)/(1+tan^2x))=((cos2x+1)(sec^2x+2tanx))/2` then `f(1/4)=`

If f((2tanx)/(1+tan^2x))=((cos2x+1)(sec^2x+2tanx))/(2) then f(4) =

f((2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+tan x))/(2) then f(x)=

If quad (2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)+2tan x))/(2) then f(4)=(i)11 (ii) 3(iii)0(iii)0

f((2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+2tan x))/(2)

If quad (2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+2tan x))/(2) then domain and range of y=f(x) are given by

tan4x = (4tanx (1-tan^2x))/(1-6tan^2x+tan^4x)

If : f(x)=(sin^(2)x)/(1+cotx)+(cos^(2)x)/(1+tanx)," then: "f'((pi)/(4))=

If : f(x)=(sin^(2)x)/(1+cotx)+(cos^(2)x)/(1+tanx)," then: "f'((pi)/(4))=

If int (2tan x+3)/(sin^(2)x+2cos^(2)x)dx =1_(n)(1+sec^(2)x)+ p tan^(-1)((tanx)/(q))+c ,then pq is

f(x)=(sin^(2)x)/(1+cotx)+(cos^(2)x)/(1+tanx) ,then , ((pi)/(4)) is