The KE of the photoelectrons is E when the incident wavelength is `(lamda)/(2)`. The KE becomes 2E when the incident wavelength is `(lamda)/(3)`. The work function of the metal is

The K.E of the electron is E when the incident wavelength is lamda . To increase the K.E of the electron to 2E, the incident wavelength must be

The kinetic energy of an electron is E when the incident wavelength is lamda To increase ti KE of the electron to 2E, the incident wavelength must be

The kinetic energy of an electron is E when the incident wavelength is lamda To increase ti KE of the electron to 2E, the incident wavelength must be

Maximum kinetic energy of a photoelectron is E when the wavelength of incident light is lambda . If energy becomes four times when wavelength is reduced to one thrid, then work function of the metal is

Maximum kinetic energy of a photoelectron is E when the wavelength of incident light is lambda . If energy becomes four times when wavelength is reduced to one thrid, then work function of the metal is

When the incident wavelengths are lamda and lamda//2 the kinetic energies of the emitted photo electrons are E and 2E. The work function of the metal is

When the incident wavelengths are lamda and lamda//2 the kinetic energies of the emitted photo electrons are E and 2E. The work function of the metal is

K.E. of photo electron is E when incident frequency is lambda_(1) . It is 2E when incident frequency is lambda_(2) . The relation between the wavelength is