If int(k)/(sin(x-a)cos(x-b))dx=log[(sin(...

If `int(k)/(sin(x-a)cos(x-b))dx=log[(sin(x-a))/(cos(x-b))]+c`, then `k=`

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If int(k)/(sin(x-a)sin(x-b))dx=log[(sin(x-a))/(sin(x-b))]+c, then k=

If int(k)/(cos(x-a)cos(x-b))dx=log[(cos(x-a))/(cos(x-b))]+c , then k=

int (sin(x-a))/(cos (x-b))dx=

int(sin(x-a)dx)/cos(x-b)

int(sin(x+a))/(cos(x-b))dx=

int(dx)/(cos(x-a)sin(x-b))=

If int (1)/(sin (x -a ) cos (x -b)) dx = A log | (sin (x -a))/( cos (x -b ))| + B. Then

int(dx)/(sin x(a+b cos x))

int(cos(x-a))/(sin(x+b))dx=

int(cos(x-a))/(sin(x+b))dx

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