If `|veca|=3` and `-1 <= k <= 2`, then `|kveca|` lies in the interval

If |veca | =3 and -1 le k le 2, then |k veca| lies in the interval :

I |veca|=3 nd -4lekle1, then what can you say about |kaveca| ?

I |veca|=3 and -4lekle1, then what can you say about |kveca| ?

If |veca|=3 , what is |5veca| .

If |veca|=3 , what is : |-2veca| .

If |veca|=3 , what is : |0veca| ?

If |veca|=3, |vecb|=1 and |veca+vecb|=|veca-vecb| , then |veca xx vecb| is:

Let vecr be a unit vector satisfying vecr xx veca = vecb, " where " |veca|= sqrt3 and |vecb| = sqrt2 , then (a)vecr= 2/3(veca+ veca xx vecb) (b) vecr= 1/3(veca+ veca xx vecb) (c) vecr= 2/3(veca- veca xx vecb) (d) vecr= 1/3(-veca+ veca xx vecb)

If veca=(3,1) and vecb=(1,2) represent the sides of a parallelogram then the angle theta between the diagonals of the paralelogram is given by (A) theta=cos^-1(1/sqrt(5)) (B) theta=cos^-1(2/sqrt(5)) (C) theta=cos^-1 (1/(2sqrt(5))) (D) theta = pi/2

If veca=(3,1) and vecb=(1,2) represent the sides of a parallelogram then the angle theta between the diagonals of the paralelogram is given by (A) theta=cos^-1(1/sqrt(5)) (B) theta=cos^-1(2/sqrt(5)) (C) theta=cos^-1 (1/(2sqrt(5))) (D) theta = pi/2