For the previous question, the acceleration of the particle at any time `t` is `:`

1) The displacement of a body at any time t after starting is given by s=15t-0.4t^(2) .The velocity of the body will be 7ms^(-1) after time = ? 2) for the previous question,the acceleration of the particles at any time is:

In the previous question , the activity of the sample after time t will be

A particle is moving in circular path with constant acceleration. In time t after the beginning of motion the direction of net acceleration is at 30^(@) to the radius vector at that instant. The angular acceleration of the particle at that time t is

The x and y coordinates of the particle at any time are x=5t-2t^(2) and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:

The x and y coordination of the particle at any time are x=5t - 2t^2 and y =10 t respectively , where x and y are in metres and t in seconds . The acceleration of the particle at t=2s is:

The x and y coordinates of the particle at any time are x=5t-2t^(2) and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is: