A stone is released from the top of a cliff .Another particles is simultaneously projected `v=10 m/sec` from the bottom of the cliff if they meet after 2 second find the height of the cliff.

Two paarticles 1 and 2 are projected simultaneusly with velocities v_(1) and v_(2) , respectively. Particle 1 is projectected vertically up from the top of a cliff of heitht h and particle 2 is projected vertically up from the bottom of the cliff. If the bodies meet (a) above the top of the cliff, (b) between the top and bottom of the the cliff, and (c ) below the bottom of the cliff, find the time of meeting of the particles. .

Two paarticles 1 and 2 are projected simultaneusly with velocities v_(1) and v_(2) , respectively. Particle 1 is projectected vertically up from the top of a cliff of heitht h and particle 2 is projected vertically up from the bottom of the cliff. If the bodies meet (a) above the top of the cliff, (b) between the top and bottom of the the cliff, and (c ) below the bottom of the cliff, find the time of meeting of the particles. .

A ball is projected downward from the top of a cliff of height h with an initial speed v.Another ball is simultaneously projected vertically up from the bottommost of the cliff with the same speed.When do they meet?

A ball is projected downward from the top of a cliff of height h with an initial speed v.Another ball is simultaneously projected vertically up from the bottommost of the cliff with the same speed.When do they meet?

A stone dropped from a cliff hits the ground in 4 sec. Height of the cliff is

A stone dropped from a cliff hits the ground in 4 sec. Height of the cliff is

Two bodies 1 and 2 are projected simultaneously with velocities v_1 = 2ms^(-1) and v_2 = 4ms^(-1) respectively. The body 1 is projected vertically up from the top of a cliff of height h = 10m and the body 2 is projected vertically up from the bottom of the cliff. If the bodies meet, find the time (in s) of meeting of the bodies.

Two bodies 1 and 2 are projected simultaneously with velocities v_1 = 2ms^(-1) and v_2 = 4ms^(-1) respectively. The body 1 is projected vertically up from the top of a cliff of height h = 10 and the body 2 is projected vertically up from the bottom of the cliff. If the bodies meet, find the time (in s) of meeting of the bodies.