The length of a simple pendulum is `1 m`. The bob is given a velocity `7 ms^(-1)` in horizontal direction from mean position. During upward motion of bob, if the string breaks when the bob is horizontal, then the maximum vertical height of ascent of bob from rest position is

The tension in the string of a simple pendulum is maximum, when the bob of the pendulum

A simple pendulum of mass m and length L is held in horizontal position. If it is released from this position, then find the angular momentum of the bob about the point of suspension when it is vertically below the point of suspension.

The maximum displacement of a bob from its mean position is called its amplitude.

Mass of the bob of a simple pendulum of length L is m . If the bob is projected horizontally from its mean position with velocity sqrt(4 gL) , then the tension in the string becomes zero after a vertical displacement of

A simple pendulum is released from rest with the string in horizontal position. The vertical component of the velocity of the bob becomes maximum, when the string makes an angle theta with the vertical. The angle theta is equal to

The bob of a simple pendulum of length L, is displaced through 90^(@) , from its mean position and then released. What will be the tension in the string when the bob of mass m will be its lowest position ?

The mass of a simple pendulum bob is 100 gm. The length of the pendulum is 1 m. The bob is drawn aside from the equilibrium position so that the string makes an angle of 60^(@) with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be

Length of a simple pendulum is 2m and mass of its bob is 2 kg if the tension in the string exceeds 100 N , it will break . If g = ms^(-2) and the bob is whirled in a horizontal plane , the maximum angle through which the sting can make vertical during ratating is