An element X has \(IE_{1},IE_{2}\text{ } and\text{ } IE_{3}\) are 738kJ/mol,1451kJ/mol and 7733kJ/mol respectively. "X'" would be (I.E = lonization energy)

First, second & third ionization energies are 737, 1045 & 7733 KJ//mol respectively. The element can be :

For an element (X) the successive ionisation energies, IE_(1), IE_(2), IE_(3), IE_(4) and IE_(5) are 800, 2427, 3658, 25024 and 32824 kJ mol^(-1) respectively, then that what is the number of valence electrons present in the element?

The heat of atomisation of PH_(3)(g) and P_(2)H_(4)(g) are 954 kJ mol^(-1) and 1485 kJ mol^(-1) respectively. The P-P bond energy in kJ mol^(-1) is

Bond energies of H-H and Cl-Cl are "430 kJ mol"^(-1) and "242 kJ mol"^(-1) respectively. DeltaH_(f) for HCl is "91 kJ mol"^(-1) . What will be the bond energy of H-Cl ?

An element X has IE and EA respectively 275 and 1450 kJ mol^(-1) . The electronegativity of element according to Pauling scale is