The angle between one of the diagonals of a cube and one of its edge is `theta` then `sqrt(3)cos theta=`

The angle between a diagonal of a cube and one of its edges is

The angle between diagonal of a cube and diagonal of a face of the cube will be

Find the angle between the diagonals of a cube with edges of length "a".

If sin theta+sqrt(3)cos theta>=1 then

cos theta - sqrt3 sin theta = 1

If theta is tbe acute angle between the diagonals of a cube, then which one of the following is correct?

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cos beta)/(sin 2 theta) is equal to:

If theta is the acute angle between the diagonals of a cube then which one of the following is correct

If veca=(3,1) and vecb=(1,2) represent the sides of a parallelogram then the angle theta between the diagonals of the paralelogram is given by (A) theta=cos^-1(1/sqrt(5)) (B) theta=cos^-1(2/sqrt(5)) (C) theta=cos^-1 (1/(2sqrt(5))) (D) theta = pi/2