A small blockofmass 'm' is released from rest at the top of a rough inclined plane as shown The coefficient of friction between the block and inclined plane is `'mu'` Using work-energy theorem, find the speed of block as it passes the lowest point.

A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is mu then .

A block is released from rest from point on a rough inclined place of inclination 37^(@). The coefficient of friction is 0.5.

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is

A block of mass m=4kg is placed oner a rough inclined plane as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . A force F=10N is applied on the block at an angle of 30^(@) .

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A block of mass m is placed at rest on an inclination theta to the horizontal.If the coefficient of friction between the block and the plane is mu , then the total force the inclined plane exerts on the block is

A block of mass 1kg is released from rest from the top of an inclined plane of inclination 45^(@) .The coefficient of friction between block and the inclined plane varies with distance x from top position as mu=1/4(1+x) where x is in meter. Then block will have maximum speed after travelling a distance of ?

A block of mass m slides down an inclined plane of inclination theta with uniform speed. The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is