Home
Class 11
PHYSICS
5 moles of oxygen are heated at constan...

5 moles of oxygen are heated at constant volume from 10C to 20C ,the change in internal energy of a gas.,[Cp=7.03calmol(-1)deg(-1) & R=8.31Jmol-1deg-1]

Promotional Banner

Similar Questions

Explore conceptually related problems

5 moles of oxygen are heated at constant volume from 10^(@)C to 20^(@)C . The change in internal energy of a gas. [C_(P)=7.03 cal mol^(-1) deg^(-1) and R=8.3J mol^(-1) deg^(-1)]

5 mole of oxygen are heated at constant volume from 10^(@)C "to" 20^(@)C . What will be the change in internal energy of the gas? Gram molar specific heat of gas at constant pressure =8cal. "Mole"^(-1).^(@)C^(-1) and R=8.36J "mole"^(-1).^(@)C^(-1) .

5 mole of oxygen are heated at constant volume from 10^(@)C to 20^(@)C . What will be the change in the internal energy of gas? The molar heat capacity of oxygen at constant pressure, C_(P)=7.03calmol^(-1)k^(-1) and R=2calmol^(-1)k^(-1)

5' moles of oxygen is heated at constant volume from 10^(@)C to 20^(@)C . What will be the change in the internal energy of the gas in calories? (For the gas C_(P)=7cal//gm" "mol//.^(@)C&R=2cal//mol" ".^(@)C )

The temperature of 5 mol of gas which was held at constant volume was change from 100^(@)C to 120^(@)C . The change in internal energy was found to ve 80 J . The total heat capacity of the gas at constant volume will be equal to

Molar heat capacity of an ideal gas at constant volume is given by C_(V)=2xx10^(-2)J (in Joule). If 3.5 mole of hits ideal gas are heated at constant volume from 300K to 400K the change in internal energy will be

One mole of a gas absorbs 200 J of heat at constant volume. Its temperature rises from 298 K to 308 K. The change in internal energy is :-

1 mole of gas having C V =20J K − 1 m o l − 1 is heated at constant volume through 10∘ C .Then increase in its internal energy is

One mole of an ideal gas with gamma=1.4 is adiabatically compressed so that its temperature rises from 27^(@)C to 34^(@)C . The change in the internal energy of the gas is (R=8.3J mol^(-10k^(-1)))