In `/_\ABC` ,if `AB=sqrt(2),AC=sqrt(20),B=(3,2,0),C=(0,1,4)` and `D` is the midpoint of `BC` then `AD=`

In triangle ABC ,if AB=sqrt(2),AC=sqrt(20) ,B=(3,2,0),C=(0,1,4) and D is the midpoint of BC then AD=

In any triangle ABC,prove that AB^(2)+AC^(2)=2(AD^(2)+BD^(2)), where D is the midpoint of BC .

In ABC, the coordinates of B are (0,0),AB=2,/_ABC=(pi)/(3), and the middle point of BC has coordinates (2,0) .The centroid o the triangle is ((1)/(2),(sqrt(3))/(2))(b)((5)/(3),(1)/(sqrt(3)))(4+(sqrt(3))/(3),(1)/(3))( d) none of these

In right-angled triangle ABC in which /_C=90^(@), if D is the mid-point of BC, prove that AB^(2)=4AD^(2)-3AC^(2)

In /_ABC,AB=AC and D is any point on BC , prove that AB^(2)-AD^(2)=BD.CD

In an equilateral Delta ABC, D is the midpoint of AB and E is the midpoint of AC. Then, ar (Delta ABC) : ar (Delta ADE)=?

In triangle ABC,D is the midpoint of BC and AD is perpendicular to AC. Then cos A.cos C=

In a triangle ABC, angleB=90^(@), D is the midpoint of AC, BD=sqrt117 . Sum of sides of AB & BC is 30 cm. Find the area of triangle ABC.

In an isoscles Delta ABC, AB= AC and D is a point on BC. Prove that AB^(2)-AD^(2)=BD*CD .