A cylindrical conductor of length `l` and radius a has conductivity near its axis as `sigma`. The conductivity of material increases linearly with the distance from axis and becomes `2 sigma` near the surface.The resistance of conductor for longitudinal current is

A cylindrical conductor of length l and uniform area of cross-section A has resistance R . Another conductor of length 2 l and resistance R of the same material has area of cross-section :

A long cylindrical conductor of cross-sectional area A and radius a is made of material whose resistivity depends only on a distance r from the axis of conductor, given by rho = c/r^(2) , where c is a constant. Find the resistance per unit length of the conductor and the electric field strength due to which a current I flows in it.

Shown a conductor of length l having a circular cross section. The radius of cross section varies linearly form a to b . The resistivity of the material is (rho) .Assuming that b-altltl ,find the resistance of the conductor.

A cylindrical wire of length L and radius r has a resistance R. The resistance of another wire of the same material but half its length and half its radius will be:

A cylindrical conductor of length l and inner radius R_(1) and outer radius R_(2) has specific resistance rho . A cell of emf epsilon is connected across the two lateral faces of the conductor. Find the current drown from the cell.