A particle moves under the effect of a force `F=kx^(2)` from `x=0` to `x=4`, the work done by force is ?

A particale moves under the effect of a force F = Cs from s = 0 to s = s_(1) . The work down in the process is

A particle is moving in x direction,under the influence of force F=pi sin pi x. Find the work done by another external agent (in J) in slowly moving a particle from x=0 to x=0.5

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres.The work done by the force is

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres.The work done by the force is

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres. The work done by the force is

A particle moves along the X - axis with velocity v = ksqrt(x) . What will be work done by the forces acting on particle during interval it moves from x = 0 to x = d ? (Assume mass of the aprticle is m ) .

A particle moves along x -axis under the action of a position dependent force F = (5x^(2) -2x) N . Work done by forces on the particle when it moves from origin to x = 3m is

A particle moves along x - axis under the action of a position dependent force F=(5x^(2)-2x)N . Work done by force on the particle when it moves from origin to x = 3 m is

A particle moves along Y - axis from y = 0 m under the influence of a force F = (9+3y+5y)^(2) N . Calculate the work done on the particle .

A particle moves under force F -5(x -2)^(3) .Motion of the particle is