Water is filled in a tank upto a height of 2m .A wooden cylinder of weight 10kg is floating on the surface of water partially immersed.If cross sectional area of tank is `1m^(2)` and that of cylinder is `0.5m^(2)`, then the total pressure (in Pa) at the bottom of tank is (`P_(o)`=atmospheric pressure )

A water tank is 20 m deep . If the water barometer reads 10 m at the surface , then what is the pressure at the bottom of the tank in atmosphere ?

If the pressure at half the depth of a tank is equal to 2/3 the pressure at the bottom of the tank, then the height of the water column in the tank is ("Atmospheric pressure "=10^5N//m^2 )

The pressure at the bottom of a water tank is 4 P, where P is .atmospheric pressure. If water is drawn out till the water level decreases by — 3/5 th, then pressure at the bottom of the tank is

A cylindrical tank is filled with water to a level of 4 m. A hole is opened at a height of 60 cm from bottom. The ratio of the area of the hole to that at cross-sectinal area at cylinder is 0.2. Then the velocity with which water is coming out is (g = 10m//s^(2))

A liquid having density 6000 kg//m^(3) stands to a height of 4 m in a sealed tank as shown in the figure. The tank contains compressed air at a gauge pressure of 3 atm . The horizontal outlet pipe has a cross-sectional area of 6 cm^(2) and 3 cm^(2) at larger and smaller sections. Atmospheric pressure = 1 atm, g = 10m//s^(2) 1 atm =10^(5) N//m^(2) . Assume that depth of water in the tank remains constant due to s very large base and air pressure above it remains constant. Based on the above information, answer the following questions. The discharge rate from the outlet is

A tank is filled by water ( rho = 10^3 kg//m^3 ). A small hole is made in the side wall of the tank at depth 10 m below water surface. A water jet emerges horizontal from the hole and falls at horizontal distance R from it. The amount of extra pressure (in terms of atmospheric pressure) that must be applied on the water surface, so that range becomes 3R on the on the ground will be (cross section area of hole is negligible and 1 atm = 105 Pa, g = 10 m/ s^2 )

A cylindrical tank is filled with water to a level of 3m. A hole is opened at a height of 52.5 cm from bottom. The ratio of the area of the hole to that of cross-sectional area of the cylinder is 0.1. The square of the speed with which water is coming out from the orifice is (Take g= 10 m//s^(2) )

A tank of base area 4 m^2 is initially filled with water up to height 2m. An object of uniform cross-section 2m^2 and height 1m is now suspended by wire into the tank, keeping distance between base of tank and that of object 1m. Density of the object is 2000kg/ m^3 . Take atmospheric pressure 1xx10^5 N//m^2 , g = 10m//s^2 . The downwards force exerted by the water on the top surface of the object is