If the sum of lengths of hypotenuse and a side of a right angled triangle is given, show that area of triangle is maximum, when the angle between them is `pi/3dot`

If the sum of the lengths of the hypotenues and a side of a right angled triangle is given, show that the area of the triangle is maximum when the angle between them is pi/3 .

If the sum of the lengths of the hypotenuse and another side of a right-angled triangle is given,show that the area of the triangle is maximum when the angle between these sides is (pi)/(3).

If the sum of a side and hypotenuse of a right angled triangle is given then show that area of triangle will be maximum when the angle between side and the hypotenuse is pi//3 .

If the length of the hypotenuse of a right angled triangle is 10 cm, then what is the maximum area of such a right angled triangle?

The maximum area of a right angled triangle with hypotenuse h is

In the right triangle BAC, angle A=pi/2 and a+b=8 . The area of the triangle is maximum when angle C , is

Prove that the perimeter of a right-angled triangle of given hypotenuse is maximum when the triangle is isosceles