A particle is oscillating according to the equation `X=7 cos 0.5 pit`, where t is in second. The point moves from the position of equilibrium to maximum displacement in time

A particle is osicllating according to the equation X= 7 cos (0.5 pi t) , where t is in second. The point moves from the position of equilibrium to maximum displacement in time

A particle is oscillating according to the equation x = 8 cos pi t , where 't' is in second. The particle moves from the position of equilibrium to maximum displacement in time

A particle is oscillating according to the equation x = 10cos2pit , where 't' is in seconds. The particle moves from the position of maximum displacement to equilibrium in time.

A particle oscillates, according to the equation x = 5 cos (pit//2) m. Then the particle moves from equilibrium position to the position of maximum displacement in time of

In what time after its motion begins, will a particle oscillating according to the equation, y=7 sin 0.5 pi t move from the mean position to maximum displacement ?

How much time will a particle oscillating according to equation y = 10 sin (0.9 pit )m take to move from mean position to position of maximum displacement ?

A particle oscillates as per the equation x = (7 cos 0.5 pi t)m , the time taken by the particle to move from the mean position to a point 3.5m away is

A particle oscillates with S.H.M. according to the equation x = 10 cos ( 2pit + (pi)/(4)) . Its acceleration at t = 1.5 s is

A body oscillates with SHM according to the equation x(t)=5cos(2pit+pi//4) where t is in second and x in metres. Calculate (a) displacement at t=0 (b) time period (c) initial velocity