A body of mass 5 kg starts from the origin with an initial velocity `vecu=30hati+40hatjms^(-1)`. If a constant force `vecF=-(hati+5hatj)N` acts on the body, the time in which the y-component of the velocity becomes zero is

A body of mass 5 kg starts from the origin with an initial velocity bar(u)=(30hati+40hatj)ms^(-1) .If a constant force (-6hati-5hatj)N acts on the body, the time in velocity, which the y-component of the velocity becomes zero is.

A body of mass 5 kg statrs from the origin with an initial velocity vec(u) = (30 hat(i) + 40 hat(j)) ms^(-1) . If a constant force (-6 hat(i) - 5 hat(j))N acts on the body, the time in which they component of the velocity becomes zero is

A particular has initial velocity , v=3hati+3hatj and a constant force F=4hati-3hatj acts on it. The path of the particle is

A body of mass 2kg is moving with a velocity of vecu=3hati+4hatj m//s .A steady force vecF=hati-2hatj N begins to act on it. After four second, the body will be moving along.

A body of mass 5 kg starts from the origin with an intial with an intial velocity vec (u) = 30hat(i) + 40hat(j). . If the body collides with a wall and after collision its velocity becomes vec(v) = - 30 hat (i) + 40 hat (j) , then what is change in momentum of body ?

A particle moves with the velocity vecv=(5hati+2hatj-hatk)ms^(-1) under the influence of a constant force, vecF=(2hati+5hatj-10hatk)N. The instantaneous power applied is

A body of mass 5 kg is moving with velocity of v=(2hati+6hatj)ms^(-1) at t=0s. After time t=2s, velocity of body is (10 hati+6 hatj) , then change in momentum to body is