A=(1,3,-2) is a vertex of triangle ABC whose centroid is G=(-1,4,2) then length of median through A is
`sqrt(21)`
`3sqrt(21)`
`sqrt(21)/2`
`(3sqrt(21))/(2)`

(1)/(sqrt(21+4x-x^(2)))

if sqrt(10+-2sqrt(21))=sqrt(a)+-sqrt(3) then a=

(4)/(sqrt(10-2sqrt(21))) =______.

sqrt(21-4sqrt5+8sqrt3-4sqrt12)=

If A(1,-1,2),B(2,1,-1)C(3,-1,2) are the vertices of a triangle then the area of triangle ABC is (A) sqrt(12) (B) sqrt(3) (C) sqrt(5) (D) sqrt(13)

(sqrt(15)+sqrt(35)+sqrt(21)+5)/(sqrt(3)+2sqrt(5)+sqrt(7))=?

3sqrt(42875)-?=21

The equation of the base of an equilateral triangle ABC is x+y=2 and the vertex is (2,-1). The area of the triangle ABC is: (sqrt(2))/(6) (b) (sqrt(3))/(6) (c) (sqrt(3))/(8) (d) None of these