Home
Class 11
PHYSICS
A boy of mass m climbs up a conveyor bel...

A boy of mass m climbs up a conveyor belt with a constant acceleration. The speed of the belt is `v=sqrt(gh//6)` and the coefficient of friction between the body and conveyor belt is `mu=(5)/(3sqrt3)`. The boy starts from A and moves with the maximum possible acceleration till he reaches the highest point B.

Work done by gravity to w.r.t. the conveyor belt is

Promotional Banner

Similar Questions

Explore conceptually related problems

A boy of mass m climbs up a conveyor belt with a constant acceleration. The speed of the belt is v=sqrt(gh//6) and the coefficient of friction between the body and conveyor belt is mu=(5)/(3sqrt3) . The boy starts from A and moves with the maximum possible acceleration till he reaches the highest point B. Work done by the boy is

A boy of mass m climbs up a conveyor belt with a constant acceleration. The speed of the belt is v=sqrt(gh//6) and the coefficient of friction between the body and conveyor belt is mu=(5)/(3sqrt3) . The boy starts from A and moves with the maximum possible acceleration till he reaches the highest point B. Work done by the boy is

A boy of mass m climbs up a conveyor belt with a constant acceleration. The speed of the belt is v=sqrt(gh//6) and the coefficient of friction between the body and conveyor belt is mu=(5)/(3sqrt3) . The boy starts from A and moves with the maximum possible acceleration till he reaches the highest point B. Work done by friction on the boy is

A boy of mass m climbs up a conveyor belt with a constant acceleration. The speed of the belt is v=sqrt(gh//6) and the coefficient of friction between the body and conveyor belt is mu=(5)/(3sqrt3) . The boy starts from A and moves with the maximum possible acceleration till he reaches the highest point B. The time taken by the boy to reach the height h is

A boy of mass m climbs up a conveyor belt with a constant acceleration. The speed of the belt is v=sqrt(gh//6) and the coefficient of friction between the body and conveyor belt is mu=(5)/(3sqrt3) . The boy starts from A and moves with the maximum possible acceleration till he reaches the highest point B. The time taken by the boy to reach the height h is

A block is gently placed on a conveyor belt moving horizontal with constant speed After t = 4s the velocity of the block becomes equal to velocity of the belt If the coefficient of friction between the block and the belt is mu = 0.2 , then the velocity of the conveyor belt is .

A block is gently placed on a conveyor belt moving horizontal with constant speed After t = 4s the velocity of the block becomes equal to velocity of the belt If the coefficient of friction between the block and the belt is mu = 0.2 , then the velocity of the conveyor belt is .

A suitcase is gently dropped on a conveyor belt moving at 3ms^(-1) If the coefficient of friction between the belt and suitcase is 0.5 how far will the suitcase move on the belt before coming to rest ?