Two integers `x and y` are chosen (with replacement) at random from `{x:0lexle10, x` is an integer). If the probability for `|x-y|le5` is `p,` then the value of `(121p)/13` is

Two integers x and y are chosen (with replacement) at random from {x:0<=x<=10,x is an integer).If the probability for |x-y|<=5 is p, then the value of (121p)/(13) is

Two integers x and y are chosen one by one with replacement at random from the set {x =0 le x le 10 and x is an integer}. Find the probability that |x-y| le 5 .

Two distinct integers x and y are chosen, without replacement, at random from the set { x , y | 0 le x le 10 , 0 le y le 10 , x and y are in integers} the probability that |x - y| le 5 is :

Two distinct integers x and y are chosen, without replacement, at random from the set { x , y | 0 le x le 10 , 0 le y le 10 , x and y are in integers} the probability that |x - y| le 5 is :

Two integers x and y are chosen with replacement out of the set {0, 1, 2, . . . 10}. The probability that |x - y| doesn't exceed 5 is

Two integers x and y are chosen with replacement out of the set {0, 1, 2, . . . 10}. The probability that |x - y| doesn't exceed 5 is

Two integers x and y are chosen with replacement out of the set {0,1,2,3...,10}. Then find the probability that |x-y|>5

Two integers x and y are chosen one by one with replacement from 0, 1, 2,…,100. Find the probability that |x - y| le 3 .