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Find the equation of the circle through ...

Find the equation of the circle through the points of intersection of the circles `x² + y^2 - 4x – 6y - 12 = 0` and `x² + y^2 + 6x + 4y - 12 = 0` and cutting the circle `x² + y^2 - 2x - 4 = 0` orthogonally.

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Find the equation of the circle through the points of interrection of the circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+6x+4y-12=0 and cutting the circle x^(2)+y^(2)-2x-4=0 orthogonally.

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