The equation of the tangents drawn from the origin to the circle `x^(2)+y^(2)-2gx-2fy+f^(2)=0` is

Tangents drawn from the origin to the circle x^(2)+y^(2)+2gx+2fy+f^(2)=0 are perpendicular if

The tangents drawn from the origin to the circle : x^2+y^2-2gx-2fy+f^2=0 are perpendicular if:

Find the equation of the pair of tangents from the origin to the circle x^2 + y^2 + 2gx + 2fy+k^2 = 0 , and show that their intercept on the line y = h is 2hk/(k^2-g^2) times the radius of the circle.

If tangents are drawn from origin to the circle x^(2)+y^(2)-2x-4y+4=0, then

The condition that the pair of tangents drawn from the origin to the circle x^(2)+y^(2)+2gx+2fy+c=0 may be at right angles is

The squared length of the intercept made by the line x=h on the pair of tangents drawn from the origin to the circle x^2+y^2+2gx+2fy+c=0 is

The condition that the pair of tangents drawn from origin to the circle x^(2)+y^(2)+2gx+2fy+c=0 may be at right angle is

The length of the tangent drawn from any point on the circle x ^(2) +y^(2) +2gx+2fy+c_(1) =0 to the circel x ^(2)+y^(2) +2gx+2fy+c_(2) =0 is-