If in the hydrogen atom P.E. At `oo` is chosen to be 13.6 eV then the ratio of T.E. to K.E.. For `1^(st)` orbit of H-atom is

If the P.E. of an electron in hydrogen atom is -27.2 eV , then its T.E. is

In hydrogen atom, energy of first excited state is-3.4eV. The K.E. of the same orbit of H-atom is

If the 1st ionisation energy of H atom is 13.6 eV then the 2nd ionisation energy of He atom is

In hydrogen atom, energy of first excited state is -3.4 eV. Then find out the K.E. of the electron in the same orbit of hydrogen atom.

The magnetude of the P.E. of the electron in the first orbit of the Bohr's atom is E. Its K.E. is

The binding energy of hydrogen atom in the lowest orbit of electron is 13.6 eV. To eject electron from the three lowest orbits of hydrogen atoms , the required energies energies (in eV ) are ______ .