If tan px = cot qx then the solutions are in

If the equation tan (P cot x) = cot (P tan x) has a solution in x in (0, pi) - {(pi)/( 2)} , then

If tan A, tan B, tan C are the solutions of the equation x^(3)-k^(2)x^(2)-px+2k+1=0 , then Delta ABC is

If tan alpha and tan beta are two solutions of x^(2)-px +q = 0, cot alpha and cot beta are the roots of x^(2)- rx +s = 0 then the value of rs is equal to

If tan alpha and tan beta are two solutions of x^(2)-px +q = 0, cot alpha and cot beta are the roots of x^(2)- rx +s = 0 then the value of rs is equal to

If tan alpha and tan beta are two solutions of x^(2)-px +q = 0, cot alpha and cot beta are the roots of x^(2)- rx +s = 0 then the value of rs is equal to

If (1+px)/(1-px)sqrt((1-qx)/(1+qx))=1 , then what are the non-zero solutions or x ?

If tan^(2)2 theta=cot^(2)alpha then the general solution is

Let the equation of the pair of lines, y = px and y = qx, can be written as (y – px) (y – qx) = 0. Then the equation of the pair of the angle bisectors of the lines x^2 – 4xy – 5y^2 = 0 is:

()123 $1. In a triangle ABC, a, b and c are the sides of the triangle satisfying the relation r1 + r2 = r3-r then the perimeter of the triangle 2ab a +b-c ab a +c-b ab a-b-c bc b+c-a 62. In ?ABC, which is not right angled, if p = sinA sinB sinc and q = cosA cosB cosc. Then the equation having roots tanA, tanB and tanC is (1) qxs_px® + (1+4)x-p=0 (2) qx3 + 2px" + qx-p=0 (3) qxs_ px2 + (2 + q)x + pq = 0 (4) qxs_px2 + qx + p = 0