Find the equation of the circle which bisects the circumference of the circle `x^(2) + y^(2) + 2y - 3 = 0` and touches the straight line y = x at the origin.

A circle bisects the circumference of the circle x^(2)+y^(2)+2y-3=0 and touches the line x=y at the point (1,1). Its radius is

A circle bisects the circumference of the circle x^2+ y^2 +2y -3=0 and touches the line x= y at the point (1, 1) . Its radius is

If the circle x^(2)+y^(2)=4 bisects the circumference of the circle x^(2)+y^(2)-2x+6y+a=0 , then 'a' equals

Show that the circle x^2+y^2+4x+4y-1=0 bisects the circumference of the circle x^2+y^2+2x-3=0 .

Show that the circle x^2+y^2+4x+4y-1=0 bisects the circumference of the circle x^2+y^2+2x-3=0 .

Find the equation of the circle which touches the line x-y=0 at origin and bisect the circumference of the circle x^(2)+y^(2)+2y-3=0

Find the equation of the straight line which passes through the centre of the circle x^(2) + y^(2) + 2x + 2y- 23 = 0 and is perpendicular to the straight line x-y+8 = 0.

If the circle x^(2)+y^(2)+4x+22y+c=0 bisects the circumference of the circle x^(2)+y^(2)-2x+8y-d=0 then c+d

Find the equation of the circle which passes through the points of intersection of the circle x^(2) + y^(2) + 4(x+y) + 4 = 0 with the line x+y+2 = 0 and has its centre at the origin.