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"If " P(AcupB)=P(AcapB)" for any two eve...

"If " P(AcupB)=P(AcapB)" for any two events A and B, then"`

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Prove that P(A)= P(AcupB)+P(AcapB) , where A and B are any two events associated with an experiment.

Statement-1 Let A and B be the two events, such that P(AcupB)=P(AcapB) , then P(AcapB')=P(A'capB)=0 Statement-2 Let A and B be the two events, such that P(AcupB)=P(AcapB), then P(A)+P(B)=1

Statement-1 Let A and B be the two events, such that P(AcupB)=P(AcapB) , then P(AcapB')=P(A'capB)=0 Statement-2 Let A and B be the two events, such that P(AcupB)=P(AcapB), then P(A)+P(B)=1

Statement-1 Let A and B be the two events, such that P(AcupB)=P(AcapB) , then P(AcapB')=P(A'capB)=0 Statement-2 Let A and B be the two events, such that P(AcupB)=P(AcapB), then P(A)+P(B)=1

Statement-1 Let A and B be the two events, such that P(AcupB)=P(AcapB) , then P(AcapB')=P(A'capB)=0 Statement-2 Let A and B be the two events, such that P(AcupB)=P(AcapB), then P(A)+P(B)=1

For two given event A and B, P(AcapB) is

For two given event A and B, P(AcapB) is

For two given event A and B, P(AcapB) is