The ratio of the area of triangle inscribed in ellipse `x^2/a^2+y^2/b^2=1` to that of triangle formed by the corresponding points on the auxiliary circle is 0.5. Then, find the eccentricity of the ellipse. (A) `1/2` (B) `sqrt3/2` (C) `1/sqrt2` (D) `1/sqrt3`

The ratio of the area of triangle inscribed in ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 to that of triangle formed by the corresponding points on the auxiliary circle is 0.5. Then,find the eccentricity of the ellipse.(A) (1)/(2) (B) (sqrt(3))/(2) (C) (1)/(sqrt(2))(D)(1)/(sqrt(3))

The ratio of any triangle PQR inscribed in an ellipse x^2/a^2+y^2/b^2=1 and that of triangle formed by the corresponding points on the auxilliary circle is b/a .

The ratio of any triangle PQR inscribed in an ellipse x^2/a^2+y^2/b^2=1 and that of triangle formed by the corresponding points on the auxilliary circle is b/a .

The ratio of any triangle PQR inscribed in an ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and that of triangle formed by the corresponding points on the auxilliary circle is (b)/(a) .

The ratio of ordinates of a point on ellipse and its corresponding point on auxiliary circle is (2sqrt(2))/(3) then its eccentricity is

If the ratio of the ordinate of a point on ellipse and its corresponding point on auxiliary circle is (2sqrt(2))/(3) then its eccentricity is

There are exactly two points on the ellipse x^2/a^2+y^2/b^2=1 ,whose distance from its centre is same and equal to sqrt((a^2+2b^2)/2) . The eccentricity of the ellipse is: (A) 1/2 (B) 1/sqrt2 (C) sqrt2/3 (D) sqrt3/2

Pa n dQ are the foci of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 and B is an end of the minor axis. If P B Q is an equilateral triangle, then the eccentricity of the ellipse is 1/(sqrt(2)) (b) 1/3 (d) 1/2 (d) (sqrt(3))/2

Pa n dQ are the foci of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 and B is an end of the minor axis. If P B Q is an equilateral triangle, then the eccentricity of the ellipse is 1/(sqrt(2)) (b) 1/3 (d) 1/2 (d) (sqrt(3))/2