A particle of mass m moves in a one dimensional potential energy `U(x)=-ax^2+bx^4`, where a and b are positive constant. The angular frequency of small oscillation about the minima of the potential energy is equal to

If a particle of mass m moves in a potential energy field U=U_(0)-ax+bx^(2) where U_(0) , a and b are positive constants.Then natural frequency of small oscillations of this particle about stable equilibrium point is (1)/(x pi)sqrt((b)/(m)) . The value of x is?

The potential energy of a particle of mass 'm' situated in a unidimensional potential field varies as U(x) = U_0 [1- cos((ax)/2)] , where U_0 and a are positive constant. The time period of small oscillations of the particle about the mean position-

The potential energy of a particle of mass 'm' situated in a unidimensional potential field varies as U(x) = U_0 [1- cos((ax)/2)] , where U_0 and a are positive constant. The time period of small oscillations of the particle about the mean position-

A particle of mass m moving along x-axis has a potential energy U(x)=a+bx^2 where a and b are positive constant. It will execute simple harmonic motion with a frequency determined by the value of

A particle of mass m moving along x-axis has a potential energy U(x)=a+bx^2 where a and b are positive constant. It will execute simple harmonic motion with a frequency determined by the value of

A particle of mass m moving along x-axis has a potential energy U(x)=a+bx^2 where a and b are positive constant. It will execute simple harmonic motion with a frequency determined by the value of

A particle of mass m is located in a one dimensional potential field where potential energy is given by V(x) = A(1- cos Px) , where A and P are constant . The period of small oscillations of the particle is