The initial rate of increase of current, when a battery of emf 6 V is connected in series with an inductance of 2 H and resistance `12Omega` , is

A parallel combination of three resistances of 6 Omega, 12 Omega and 12 Omega is connected in series with an electric cell of emf 1.5 V and internal resistance 2 Omega . Find out the currents through the three resistances.

A certain length of a uniform wire of resistance 12Omega is bent into a circle and two points, a quarter of circumference apart, are connected to a battery of emf 4 V and internal resistance 1Omega . Find the current in the different parts of the circuit.

A certain length of a uniform wire of resistance 12Omega is bent into a circle and two points, a quarter of circumference apart, are connected to a battery of emf 4 V and internal resistance 1Omega . Find the current in the different parts of the circuit.

A coil of inductance 0.20 H is connected in series with a switch and a cell of emf 1.6 V . The total resistance of the circuit is 4.0 Omega . What is the initial rate of growth of the current when the switch is closed?

A coil of inductance 0.20 H is connected in series with a switch and a cell of emf 1.6 V . The total resistance of the circuit is 4.0 Omega . What is the initial rate of growth of the current when the switch is closed?

An inductor with an inductance of 2.5H and a resistance of 8Omega is connected to the terminals of a battery with an EMF 6V and negligible internal resistance. Find (a) The initial rate of increase of current in the circuit (b) The rate of increase of current at the instant when the current is 0.50A (c ) The current 0.25s after the circuit is closed (d) The final steady state current

A galvanometer, together with an unknown resistance in series, is connected across two identical batteries of each 1.5 V . When the batteries are connected in series,the galvanometer records a current of 1 A , and when the batteries are connected in parallel, the current is 0.6 A . In this case, the internal resistance of the battery is 1//'**' Omega . What is the value of '**'?

Current is sent through a galvanometer of resistance 50 Omega from a battery of emf 30V and of negligible internal resistance.There is a shunt of resistance 2 Omega connected in parallel with the galvanometer.Find out the resistance that should be connected in series with the battery to get a current of 10mA through the galvanometer.

A battery of emf 4 volt and internal resistance 1 Omega is connected in parallel with another battery of emf 1 V and internal resistance 1 Omega (with their like poles connected together). The combination is used to send current through an external resistance of 2 Omega . Calculate the current through the external resistance.