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Let f(x)=x^3-3(a-2)x^2+3ax+7 and f(x) is...

Let `f(x)=x^3-3(a-2)x^2+3ax+7` and `f(x)` is increasing in `(0,1]` and decreasing is `[1,5)`, then roots of the equation `(f(x)-14)/((x-1)^2)=0` is (A) `1` (B) `3` (C) `7` (D) `-2`

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