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A radioactive nucleus X decay to a nucle...

A radioactive nucleus `X `decay to a nucleus `Y` with a decay with a decay Concept `lambda _(x) = 0.1s^(-1) , gamma ` further decay to a stable nucleus Z with a decay constant `lambda_(y) = 1//30 s^(-1)` initialy, there are only X nuclei and their number is `N_(0) = 10^(20)` set up the rate equations for the population of `X^9) Y and Z` The population of `Y` nucleus as a function of time is givenby `N_(y) (1) = N_(0) lambda_(x)l(lambda_(x) - lambda_(y))) (exp(- lambda_(y)1)) Find the time at which `N_(y)` is maximum and determine the populastion `X and Y` at that instant.

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A radioactive nucleus X decay to a nucleus Y with a decay with a decay Concept lambda _(x) = 0.1s^(-1) , gamma further decay to a stable nucleus Z with a decay constant lambda_(y) = 1//30 s^(-1) initialy, there are only X nuclei and their number is N_(0) = 10^(20) . Set up the rate equations for the population of X , Y and Z The population of Y nucleus as a function of time is given by N_(y) (1) = N_(0) lambda_(x)l(lambda_(x) - lambda_(y))( (exp(- lambda_(y)t)) Find the time at which N_(y) is maximum and determine the populations X and Z at that instant.

A radioactive nucleus X decays to a nucleus Y with a decay constant lambda_X=0.1s^-1, Y further decays to a stable nucleus Z with a decay constant lambda_Y=1//30s^-1 . Initially, there are only X nuclei and their number is N _0=10^20 . Set up the rate equations for the populations of X, Y and Z. The population of Y nucleus as a function of time is given by N_Y(t)={N _0lambda_X//(lambda_X-lambda_Y)}[exp(-lambda_Yt)-exp(-lambda_Xt)]. Find the time at which N_Y is maximum and determine the population X and Z at that instant.

A radioactive nucleus X decays to a nucleus Y with a decay constant lambda_X=0.1s^-1 , Y further decays to a stable nucleus Z with a decay constant lambda_Y=1//30s^-1 . Initially, there are only X nuclei and their number is N _0=10^20 . Set up the rate equations for the populations of X, Y and Z. The population of Y nucleus as a function of time is given by N_Y(t)={N _0lambda_X//(lambda_X-lambda_Y)}[exp(-lambda_Yt)-exp(-lambda_Xt)] . Find the time at which N_Y is maximum and determine the population X and Z at that instant.

A radioactive nucleus X decays to a nucleus Y with a decay constant lambda_X=0.1s^-1 , Y further decays to a stable nucleus Z with a decay constant lambda_Y=1//30s^-1 . Initially, there are only X nuclei and their number is N _0=10^20 . Set up the rate equations for the populations of X, Y and Z. The population of Y nucleus as a function of time is given by N_Y(t)={N _0lambda_X//(lambda_X-lambda_Y)}[exp(-lambda_Yt)-exp(-lambda_Xt)] . Find the time at which N_Y is maximum and determine the population X and Z at that instant.

In the gamma decay of a nucleus