`cosecA=4p+1/(16p)` then `cosecA+cotA=`

cos ecA=4p+(1)/(16p) then cos ecA+cot A=

[cosec A=4p+(1)/(16p) cosec A+cot A =[1)8p, 2) (1)/(8p) 3) -8p( or )(1)/(8p), 4) 8p( or )(1)/(8p)]]

The value of (cosecA + cotA +1)(cosecA - cotA + 1) - 2cosecA is: (cosecA + cotA +1)(cosecA - cotA + 1) - 2cosecA का मान है :

If sinA=1/3 then cosA. cosecA+tanA.secA=

Prove that cosecA-2cot2AcosA=sinA

1/(cosecA+cotA)=cosecA-cotA

Prove that : cosec A- cot A =(1)/(cosecA+cotA)

Prove that : cosec A- cot A =(1)/(cosecA+cotA)

(cotA-cosecA)^2=x then x=