The kinetic energy of a body of mass 5 kg is 100 J. When it is thrown up then the height to which it goes up, is`(g=10m//s^(2))`

A body of mass 5 kg is taken a height 5 m to 10 m .Find the increase in its potential energy (g=10 m s^(-2) )

The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with velocity of 2 m/s without slipping is 32.8 J. The radius of gyration of a body is ………..

Calculate the height through which a body of mass 0.5 kg is lifted if the energy spent in doing so is 10j . Take g = 10 m s^(-2)

A body of mass 5kg is thrown up vertically with a kinetic energy of 1000J . If acceleration due to gravity is 10ms^(-2) , find the height at which the kinetic energy becomes half of the original value.